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Remove TypeOrigin::RangeExpression

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This variant became unused in #30884.
This commit is contained in:
John Firebaugh 2016-10-02 16:29:20 -07:00
parent 9d4d0da7af
commit 16a979c106
1 changed files with 0 additions and 6 deletions
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6
src/librustc/infer/mod.rs
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@ -199,9 +199,6 @@ pub enum TypeOrigin {
// Computing common supertype of an if expression with no else counter-part
IfExpressionWithNoElse(Span),
// Computing common supertype in a range expression
RangeExpression(Span),
// `where a == b`
EquatePredicate(Span),
@ -231,7 +228,6 @@ impl TypeOrigin {
},
&TypeOrigin::IfExpression(_) => "if and else have incompatible types",
&TypeOrigin::IfExpressionWithNoElse(_) => "if may be missing an else clause",
&TypeOrigin::RangeExpression(_) => "start and end of range have incompatible types",
&TypeOrigin::EquatePredicate(_) => "equality predicate not satisfied",
&TypeOrigin::MainFunctionType(_) => "main function has wrong type",
&TypeOrigin::StartFunctionType(_) => "start function has wrong type",
@ -251,7 +247,6 @@ impl TypeOrigin {
&TypeOrigin::MatchExpressionArm(..) => "match arms have compatible types",
&TypeOrigin::IfExpression(_) => "if and else have compatible types",
&TypeOrigin::IfExpressionWithNoElse(_) => "if missing an else returns ()",
&TypeOrigin::RangeExpression(_) => "start and end of range have compatible types",
&TypeOrigin::EquatePredicate(_) => "equality where clause is satisfied",
&TypeOrigin::MainFunctionType(_) => "`main` function has the correct type",
&TypeOrigin::StartFunctionType(_) => "`start` function has the correct type",
@ -1742,7 +1737,6 @@ impl TypeOrigin {
TypeOrigin::MatchExpressionArm(match_span, ..) => match_span,
TypeOrigin::IfExpression(span) => span,
TypeOrigin::IfExpressionWithNoElse(span) => span,
TypeOrigin::RangeExpression(span) => span,
TypeOrigin::EquatePredicate(span) => span,
TypeOrigin::MainFunctionType(span) => span,
TypeOrigin::StartFunctionType(span) => span,