flatten nested slice patterns in HAIR construction
nested slice patterns have the same functionality as non-nested ones, so flatten them in HAIR construction. Fixes #26158.
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3 changed files with 74 additions and 10 deletions
16
src/test/compile-fail/issue-26158.rs
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16
src/test/compile-fail/issue-26158.rs
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@ -0,0 +1,16 @@
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// Copyright 2016 The Rust Project Developers. See the COPYRIGHT
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// file at the top-level directory of this distribution and at
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// http://rust-lang.org/COPYRIGHT.
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//
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// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
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// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
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// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
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// option. This file may not be copied, modified, or distributed
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// except according to those terms.
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#![feature(slice_patterns)]
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fn main() {
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let x: &[u32] = &[];
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let &[[ref _a, ref _b..]..] = x; //~ ERROR refutable pattern
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}
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@ -144,6 +144,20 @@ fn e() {
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assert_eq!(c, 1);
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}
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fn f() {
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let x = &[1, 2, 3, 4, 5];
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let [a, [b, [c, ..].., d].., e] = *x;
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assert_eq!((a, b, c, d, e), (1, 2, 3, 4, 5));
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let x: &[isize] = x;
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let (a, b, c, d, e) = match *x {
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[a, [b, [c, ..].., d].., e] => (a, b, c, d, e),
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_ => unimplemented!()
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};
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assert_eq!((a, b, c, d, e), (1, 2, 3, 4, 5));
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}
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pub fn main() {
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a();
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b();
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@ -151,4 +165,5 @@ pub fn main() {
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c();
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d();
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e();
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f();
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}
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