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Fix pretty printing an AST representing &(mut ident)

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`PatKind::Ref(PatKind::Ident(BindingMode::ByValue(Mutability::Mut), ..), ..)`
is an AST representing `&(mut ident)`. It was errorneously printed as
`&mut ident` which reparsed into a syntactically different AST.

This affected help diagnostics in the parser.
This commit is contained in:
Thomas Bahn 2020-12-19 23:13:50 +01:00
parent b1964e60b7
commit b05ab18aec
3 changed files with 28 additions and 1 deletions
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10
compiler/rustc_ast_pretty/src/pprust/state.rs
View file

@ -2420,7 +2420,15 @@ impl<'a> State<'a> {
if mutbl == ast::Mutability::Mut {
self.s.word("mut ");
}
self.print_pat(inner);
if let PatKind::Ident(ast::BindingMode::ByValue(ast::Mutability::Mut), ..) =
inner.kind
{
self.popen();
self.print_pat(inner);
self.pclose();
} else {
self.print_pat(inner);
}
}
PatKind::Lit(ref e) => self.print_expr(&**e),
PatKind::Range(ref begin, ref end, Spanned { node: ref end_kind, .. }) => {