use present tense consistently and update references
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bbf82be076
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5 changed files with 6 additions and 6 deletions
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@ -98,12 +98,12 @@ impl<'a, 'gcx, 'tcx> InferCtxt<'a, 'gcx, 'tcx> {
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(None, None) => {
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let (main_label_1, span_label_1) = if ty_sup == ty_sub {
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(format!("this type was declared with multiple lifetimes..."),
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(format!("this type is declared with multiple lifetimes..."),
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format!("...but data{} flows{} here",
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format!(" with one lifetime"),
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format!(" into the other")))
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} else {
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(format!("these two types was declared with different lifetimes..."),
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(format!("these two types are declared with different lifetimes..."),
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format!("...but data{} flows{} here",
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span_label_var1,
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span_label_var2))
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@ -8,7 +8,7 @@ error[E0623]: lifetime mismatch
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with different lifetimes...
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20 |
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21 | if x > y { x } else { y }
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| ^ ...but data flows `x` is returned here
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| ^ ...but data from `x` is returned here
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error: aborting due to previous error
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@ -8,7 +8,7 @@ error[E0623]: lifetime mismatch
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with different lifetimes...
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17 |
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18 | x
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| ^ ...but data flows from `x` is returned here
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| ^ ...but data from `x` is returned here
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error: aborting due to previous error
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@ -8,7 +8,7 @@ error[E0623]: lifetime mismatch
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with different lifetimes...
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17 |
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18 | if true { x } else { self }
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| ^^^^ ...but data flows from `self` is returned here
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| ^^^^ ...but data from `self` is returned here
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error: aborting due to previous error
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@ -4,7 +4,7 @@ error[E0623]: lifetime mismatch
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15 | fn foo(mut x: Ref) {
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| ---
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| |
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| this type was declared with multiple lifetimes...
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| this type is declared with multiple lifetimes...
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16 | x.a = x.b;
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| ^^^ ...but data with one lifetime flows into the other here
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