Parse fully-qualified associated types in generics without whitespace

This breaks code that looks like this:

    let x = foo as bar << 13;

Change such code to look like this:

    let x = (foo as bar) << 13;

Closes #17362.

[breaking-change]
This commit is contained in:
P1start 2014-12-23 13:13:49 +13:00
parent 7e11b22713
commit d9769ec383
10 changed files with 53 additions and 59 deletions

View file

@ -62,7 +62,7 @@ impl Tables {
}
let mut table16 = [0;1 << 16];
for (i, v) in table16.iter_mut().enumerate() {
*v = table8[i & 255] as u16 << 8 |
*v = (table8[i & 255] as u16) << 8 |
table8[i >> 8] as u16;
}
Tables { table8: table8, table16: table16 }

View file

@ -0,0 +1,18 @@
// Copyright 2014 The Rust Project Developers. See the COPYRIGHT
// file at the top-level directory of this distribution and at
// http://rust-lang.org/COPYRIGHT.
//
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
// option. This file may not be copied, modified, or distributed
// except according to those terms.
#![feature(associated_types)]
trait Foo {
type T;
fn foo() -> Box<<Self as Foo>::T>;
}
fn main() {}